Physics: Work & Kinetic energy

Hey, I’m doing some exercises on Kinetic Energy and Work.
And apparently sometimes I can solve the question by using either formules ((mv^2)/2) or simply the F*X for W). The question is, is it just coincidence that I have the same solution using both methods. Of course, they are both energy, perhaps there’s something I’m not seeing ?
Ty -Flesj-
Answer #1

http://en.wikipedia.org/wiki/Work_(physics)

check the first paragraph:

According to the work-energy theorem if an external force acts upon an object, causing its kinetic energy to change from Ek1 to Ek2, then the mechanical work (W) is given by:
W = (delta)Ek = Ek{2} - Ek{1} =1/2(mass) (volume^2)
where m is the mass of the object and v is the object's speed.
The mechanical work applied to an object can be calculated from the dot product of the applied force (F) and the displacement (d) of the object. This is given by:
W =Force (dot product) distance
Answer #2
So we get two formulas for W right ? F*X AND (m*v^2)/(2), where the first one is mechanic and the second one is kinetic (if I understand correctly) ?
-Flesj-
Answer #3
I think Techincally both are mechanical. and yes there are two formulas for work W= F*D= (m*v^2)/(2) . The first is obvious where W=F*D, the second where W=(m*v^2)/(2), in this case work is not equal to kinetic energy, but the change in kinetic energies ek1 and ek2. The work is what is causing the change in the kinetic energy of the object
*if i am confusing you just ignore me. I am trying to explain the wiki page ‘better’
Answer #4
Confused me at first but I get it now.
Ty alot for your help mate
Cheers – Flesj-
Answer #5
if you need help on like specific problems i can help you there, i am better at the mathematical than conceptual aspects
Answer #6
Alright, have some problems regarding graviationalforce and stuff, can be more specific tomorrow, you online during the day (msn, mail or whatever) as I have to nappy nappy now
-Flesj-