Trigonometry question

Its been a few years since i took Calculus in college. Can someone explain me this equation in detail and what it calculates. I was studding the golden mean and came across this

Answer #1
anybody?
Answer #2
I am not sure but have you tried looking for math related forums which might help you answer such question.
Answer #3
I know its calculation a function of a curve and the rate of change or relation but im not sure
Answer #4
this is simple scalar*vector operation
Answer #5
When plotted in Mathematica looks like this:
http://imageupload.org/en/file/200004/untitled-2.jpg.html
Answer #6
sime.marasovic replied: When plotted in Mathematica looks like this:
http://imageupload.org/en/file/200004/untitled-2.jpg.htmlyeah thats the eye of volure the golden relation curve. I need to understand the equation
Answer #7
This is parametric function, for each theta an (x,y) vector is given. When plotted in 2D plane, for theta ranging from 0 to 4pi, you get picture above. In the equation: (x,y) vector is represented as a row matrix (dimension 1×2). On the right side of equation expressions containing sin and cos are matrix with same dimensions too. Factors in front of matrix are scalars and they just multiply each element in matrix. After multiplying scalars with matrices, matrix addition are performed: upper elements are added an that equals x, and bottom elements are added and that equals y.
Answer #8
sime.marasovic replied: This is parametric function, for each theta an (x,y) vector is given. When plotted in 2D plane, for theta ranging from 0 to 4pi, you get picture above. In the equation: (x,y) vector is represented as a row matrix (dimension 1x2). On the right side of equation expressions containing sin and cos are matrix with same dimensions too. Factors in front of matrix are scalars and they just multiply each element in matrix. After multiplying scalars with matrices, matrix addition are performed: upper elements are added an that equals x, and bottom elements are added and that equals y.I get the general idea but still dont understand it. I appreciate your help but can you break the equation down part by part
Answer #9
Can this help you?
http://www.mediafire.com/?5odzv4vtb88r1so
Answer #10
sime.marasovic replied: Can this help you?
http://www.mediafire.com/?5odzv4vtb88r1sothanx a lot mate now I can understand it better