Anyone good with maths?

Two lorries travel from city A to city B. the first lorry leaves at 10:30 at 65km/hr. The second leaves at 10:35 traveling at 75km/hr. Both cities lie on a straight line.
Grid reference:
city a – (42, 45)
city b – (52, 40)
I need out work out the time each of the lorries arrive at the destination.
I need to construct two equations of distance in terms of time showing algebraically and graphically when the second lorry overtakes the first.
I need to calculate the shortest distance of the road.
I need to state the grid reference of the mid point between the cities.
And I need to find the equation of the perpendicular line drawn at the mid point.
My teachers a moron and won’t help me. Can’t deal with him. Seriously.
Thanks for any help though guys if anyone does attempt. Lol.
Answer #1
Report him
Answer #2
I remember there was a formula for this something like
Destination1 = Speed1 + Time1
Destination2 = Speed2 + Time2
Something like that….blurry memory
Answer #3
first find your distance between the two points
then you make a little table saying if it takes 65km/1hr then it must take <distance you found>/?hr cross multiply
do that for the second person thats the time it takes for getting from your first point to the other then add the time that they started and theres your anser to your first question
sry but for the second question your on your own cuz i got no clue what your teacher wants
to find the shortest distance beetween both points are if you stick them together and you kind of did that in the first problem[ find the distance between them]
I need to state the grid reference of the mid point between the cities.
im guessing your trying to find the point between both points so you just take the average coordinates and divide by 2 so (42+52)/2=47 (52+40)/2=46
so your midpoint is 47,46
And I need to find the equation of the perpendicular line drawn at the midpoint
ok here is going to get a bit tricky ;p you have to take the slope and then make a line equasion
ok to find the slope you gotto (Y2-Y1)/(X2-X1) wich ends up like this (40-52)/(52-41)=(-12)/(10)
now to make it perpendicular you have to flip the #’s and make it negative so (-12)/(10) will be 10/12 in perpendicularness
so thats now your a or m value in your line equasion mX+b=y so… (10/12)X+b=Y now since you dont know your b you have to put in a point and algibreakly solve b so use your midpoint that needs to be in this line so replace x as your x value and do the same for your y and it sould look like this (10/12)47+b=46 after you do your algebra to it your final result looks like this b=-6.83333333333333333333333333333333333333333333333333 you get the point now that its repeat XD and your final anser for your line equasion is (10/12)X-6.83=Y
i hope it was usefull
Answer #4
Haha. Dude that really helped (Y)
Thanks a million
Answer #5
no problem man i hope you understood it 100% xD
Answer #6
Kinda. Haha. I’ll try my best. Thanks a lot!
Answer #7
good to see people trying to help